1450355240051 has 4 divisors (see below), whose sum is σ = 1450392512472. Its totient is φ = 1450317967632.

The previous prime is 1450355239967. The next prime is 1450355240123. The reversal of 1450355240051 is 1500425530541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1450355240051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1450355239993 and 1450355240020.

It is not an unprimeable number, because it can be changed into a prime (1450355246051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18577781 + ... + 18655686.

It is an arithmetic number, because the mean of its divisors is an integer number (362598128118).

Almost surely, 2^{1450355240051} is an apocalyptic number.

1450355240051 is a deficient number, since it is larger than the sum of its proper divisors (37272421).

1450355240051 is an equidigital number, since it uses as much as digits as its factorization.

1450355240051 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 37272420.

The product of its (nonzero) digits is 60000, while the sum is 35.

The spelling of 1450355240051 in words is "one trillion, four hundred fifty billion, three hundred fifty-five million, two hundred forty thousand, fifty-one".