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145036224211 = 193751483027
BaseRepresentation
bin1000011100010011010…
…1010010011011010011
3111212100211020120120211
42013010311102123103
54334013233133321
6150343445344551
713323063364504
oct2070465223323
9455324216524
10145036224211
1156567192a0a
1224138408157
13108a5094918
14703c43cbab
153b8ce310e1
hex21c4d526d3

145036224211 has 4 divisors (see below), whose sum is σ = 145787707432. Its totient is φ = 144284740992.

The previous prime is 145036224131. The next prime is 145036224247. The reversal of 145036224211 is 112422630541.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 112422630541 = 138647894657.

It is a cyclic number.

It is not a de Polignac number, because 145036224211 - 237 = 7597270739 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145036224811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 375741321 + ... + 375741706.

It is an arithmetic number, because the mean of its divisors is an integer number (36446926858).

Almost surely, 2145036224211 is an apocalyptic number.

145036224211 is a deficient number, since it is larger than the sum of its proper divisors (751483221).

145036224211 is an equidigital number, since it uses as much as digits as its factorization.

145036224211 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 751483220.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 145036224211 its reverse (112422630541), we get a palindrome (257458854752).

The spelling of 145036224211 in words is "one hundred forty-five billion, thirty-six million, two hundred twenty-four thousand, two hundred eleven".

Divisors: 1 193 751483027 145036224211