1450642161131 has 4 divisors (see below), whose sum is σ = 1464726065712. Its totient is φ = 1436558256552.

The previous prime is 1450642161103. The next prime is 1450642161149. The reversal of 1450642161131 is 1311612460541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1450642161131 is a prime.

It is a super-2 number, since 2×1450642161131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1450642161091 and 1450642161100.

It is not an unprimeable number, because it can be changed into a prime (1450642361131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7041952136 + ... + 7041952341.

It is an arithmetic number, because the mean of its divisors is an integer number (366181516428).

Almost surely, 2^{1450642161131} is an apocalyptic number.

1450642161131 is a deficient number, since it is larger than the sum of its proper divisors (14083904581).

1450642161131 is a wasteful number, since it uses less digits than its factorization.

1450642161131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14083904580.

The product of its (nonzero) digits is 17280, while the sum is 35.

The spelling of 1450642161131 in words is "one trillion, four hundred fifty billion, six hundred forty-two million, one hundred sixty-one thousand, one hundred thirty-one".