Base | Representation |
---|---|
bin | 100000111111101011101000… |
… | …110110001010001110001011 |
3 | 201000210201202021110221121220 |
4 | 200333223220312022032023 |
5 | 123010020244410340121 |
6 | 1232344144515533123 |
7 | 42365055026345241 |
oct | 4077535066121613 |
9 | 630721667427556 |
10 | 145113671574411 |
11 | 422683a9553031 |
12 | 14338002bba1a3 |
13 | 62c8211851ca7 |
14 | 27b9779718791 |
15 | 11b9b163046c6 |
hex | 83fae8d8a38b |
145113671574411 has 4 divisors (see below), whose sum is σ = 193484895432552. Its totient is φ = 96742447716272.
The previous prime is 145113671574241. The next prime is 145113671574457. The reversal of 145113671574411 is 114475176311541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 145113671574411 - 222 = 145113667380107 is a prime.
It is a super-3 number, since 3×1451136715744113 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (145113671570411) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24185611929066 + ... + 24185611929071.
It is an arithmetic number, because the mean of its divisors is an integer number (48371223858138).
Almost surely, 2145113671574411 is an apocalyptic number.
145113671574411 is a deficient number, since it is larger than the sum of its proper divisors (48371223858141).
145113671574411 is an equidigital number, since it uses as much as digits as its factorization.
145113671574411 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48371223858140.
The product of its digits is 1411200, while the sum is 51.
The spelling of 145113671574411 in words is "one hundred forty-five trillion, one hundred thirteen billion, six hundred seventy-one million, five hundred seventy-four thousand, four hundred eleven".
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