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14514213235 = 54297675551
BaseRepresentation
bin11011000010001110…
…10101000101110011
31101110112001102112011
431201013111011303
5214211114310420
610400121543351
71022450530324
oct154107250563
941415042464
1014514213235
116178993255
122990944b57
1314a3ccc472
149b98cc44b
1559e35795a
hex3611d5173

14514213235 has 8 divisors (see below), whose sum is σ = 17421134976. Its totient is φ = 11608651200.

The previous prime is 14514213229. The next prime is 14514213257. The reversal of 14514213235 is 53231241541.

14514213235 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-14514213235 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14514213197 and 14514213206.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 316291 + ... + 359260.

It is an arithmetic number, because the mean of its divisors is an integer number (2177641872).

Almost surely, 214514213235 is an apocalyptic number.

14514213235 is a deficient number, since it is larger than the sum of its proper divisors (2906921741).

14514213235 is an equidigital number, since it uses as much as digits as its factorization.

14514213235 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 679853.

The product of its digits is 14400, while the sum is 31.

Adding to 14514213235 its reverse (53231241541), we get a palindrome (67745454776).

The spelling of 14514213235 in words is "fourteen billion, five hundred fourteen million, two hundred thirteen thousand, two hundred thirty-five".

Divisors: 1 5 4297 21485 675551 3377755 2902842647 14514213235