Base | Representation |
---|---|
bin | 11011000010111011… |
… | …00001111101101011 |
3 | 1101110221000002220212 |
4 | 31201131201331223 |
5 | 214214112030011 |
6 | 10400450411335 |
7 | 1022551150052 |
oct | 154135417553 |
9 | 41427002825 |
10 | 14520033131 |
11 | 61811a888a |
12 | 2992890b4b |
13 | 14a52894a6 |
14 | 9ba5a5399 |
15 | 59eb0708b |
hex | 361761f6b |
14520033131 has 4 divisors (see below), whose sum is σ = 14528289600. Its totient is φ = 14511776664.
The previous prime is 14520033067. The next prime is 14520033137. The reversal of 14520033131 is 13133002541.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14520033131 - 26 = 14520033067 is a prime.
It is a super-2 number, since 2×145200331312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14520033097 and 14520033106.
It is not an unprimeable number, because it can be changed into a prime (14520033137) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4125596 + ... + 4129113.
It is an arithmetic number, because the mean of its divisors is an integer number (3632072400).
Almost surely, 214520033131 is an apocalyptic number.
14520033131 is a deficient number, since it is larger than the sum of its proper divisors (8256469).
14520033131 is an equidigital number, since it uses as much as digits as its factorization.
14520033131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8256468.
The product of its (nonzero) digits is 1080, while the sum is 23.
Adding to 14520033131 its reverse (13133002541), we get a palindrome (27653035672).
The spelling of 14520033131 in words is "fourteen billion, five hundred twenty million, thirty-three thousand, one hundred thirty-one".
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