Base | Representation |
---|---|
bin | 1000011100111011110… |
… | …0111111100000110011 |
3 | 111212210122201220012111 |
4 | 2013032330333200303 |
5 | 4334340220003201 |
6 | 150412352510151 |
7 | 13330224525445 |
oct | 2071674774063 |
9 | 455718656174 |
10 | 145206016051 |
11 | 56644013048 |
12 | 2418524b357 |
13 | 10901303275 |
14 | 7056bda495 |
15 | 3b9ccbeb51 |
hex | 21cef3f833 |
145206016051 has 4 divisors (see below), whose sum is σ = 145206945000. Its totient is φ = 145205087104.
The previous prime is 145206016049. The next prime is 145206016063. The reversal of 145206016051 is 150610602541.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 145206016051 - 21 = 145206016049 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (145206016091) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 166126 + ... + 563923.
It is an arithmetic number, because the mean of its divisors is an integer number (36301736250).
Almost surely, 2145206016051 is an apocalyptic number.
145206016051 is a deficient number, since it is larger than the sum of its proper divisors (928949).
145206016051 is an equidigital number, since it uses as much as digits as its factorization.
145206016051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 928948.
The product of its (nonzero) digits is 7200, while the sum is 31.
Adding to 145206016051 its reverse (150610602541), we get a palindrome (295816618592).
The spelling of 145206016051 in words is "one hundred forty-five billion, two hundred six million, sixteen thousand, fifty-one".
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