145242544110241 has 4 divisors (see below), whose sum is σ = 145400588228800. Its totient is φ = 145084499991684.

The previous prime is 145242544110133. The next prime is 145242544110271. The reversal of 145242544110241 is 142011445242541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 145242544110241 - 2⁷ = 145242544110113 is a prime.

It is a super-2 number, since 2×145242544110241² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145242544110194 and 145242544110203.

It is not an unprimeable number, because it can be changed into a prime (145242544110271) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 79022057901 + ... + 79022059738.

It is an arithmetic number, because the mean of its divisors is an integer number (36350147057200).

Almost surely, 2^{145242544110241} is an apocalyptic number.

It is an amenable number.

145242544110241 is a deficient number, since it is larger than the sum of its proper divisors (158044118559).

145242544110241 is an equidigital number, since it uses as much as digits as its factorization.

145242544110241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 158044118558.

The product of its (nonzero) digits is 204800, while the sum is 40.

Adding to 145242544110241 its reverse (142011445242541), we get a palindrome (287253989352782).

The spelling of 145242544110241 in words is "one hundred forty-five trillion, two hundred forty-two billion, five hundred forty-four million, one hundred ten thousand, two hundred forty-one".