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14530403153 = 72075771879
BaseRepresentation
bin11011000100001010…
…00101101101010001
31101111122111221220202
431202011011231101
5214224240400103
610401500544545
71023035250260
oct154205055521
941448457822
1014530403153
116187040a52
122996252155
1314a747a5b6
149bbb045d7
155a09a4988
hex362145b51

14530403153 has 4 divisors (see below), whose sum is σ = 16606175040. Its totient is φ = 12454631268.

The previous prime is 14530403137. The next prime is 14530403171. The reversal of 14530403153 is 35130403541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14530403153 - 24 = 14530403137 is a prime.

It is a super-2 number, since 2×145304031532 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14530403053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1037885933 + ... + 1037885946.

It is an arithmetic number, because the mean of its divisors is an integer number (4151543760).

Almost surely, 214530403153 is an apocalyptic number.

It is an amenable number.

14530403153 is a deficient number, since it is larger than the sum of its proper divisors (2075771887).

14530403153 is an equidigital number, since it uses as much as digits as its factorization.

14530403153 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2075771886.

The product of its (nonzero) digits is 10800, while the sum is 29.

Adding to 14530403153 its reverse (35130403541), we get a palindrome (49660806694).

The spelling of 14530403153 in words is "fourteen billion, five hundred thirty million, four hundred three thousand, one hundred fifty-three".

Divisors: 1 7 2075771879 14530403153