145312523131 has 4 divisors (see below), whose sum is σ = 146945248200. Its totient is φ = 143679798064.

The previous prime is 145312523047. The next prime is 145312523159. The reversal of 145312523131 is 131325213541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 145312523131 - 2¹¹ = 145312521083 is a prime.

It is a super-2 number, since 2×145312523131² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 145312523093 and 145312523102.

It is not an unprimeable number, because it can be changed into a prime (145312524131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 816362401 + ... + 816362578.

It is an arithmetic number, because the mean of its divisors is an integer number (36736312050).

Almost surely, 2^145312523131 is an apocalyptic number.

145312523131 is a deficient number, since it is larger than the sum of its proper divisors (1632725069).

145312523131 is an equidigital number, since it uses as much as digits as its factorization.

145312523131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1632725068.

The product of its digits is 10800, while the sum is 31.

Adding to 145312523131 its reverse (131325213541), we get a palindrome (276637736672).

The spelling of 145312523131 in words is "one hundred forty-five billion, three hundred twelve million, five hundred twenty-three thousand, one hundred thirty-one".