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145313202235 = 543496682603
BaseRepresentation
bin1000011101010101010…
…1111000000000111011
3111220002010102112000011
42013111111320000323
54340100134432420
6150431142122351
713332665560555
oct2072525700073
9456063375004
10145313202235
1156699572673
12241b51203b7
131091a591946
14706713c4d5
153ba73e395a
hex21d557803b

145313202235 has 8 divisors (see below), whose sum is σ = 174415964400. Its totient is φ = 116223813984.

The previous prime is 145313202211. The next prime is 145313202241. The reversal of 145313202235 is 532202313541.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 145313202235 - 213 = 145313194043 is a prime.

It is a super-2 number, since 2×1453132022352 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 145313202197 and 145313202206.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3319557 + ... + 3363046.

It is an arithmetic number, because the mean of its divisors is an integer number (21801995550).

Almost surely, 2145313202235 is an apocalyptic number.

145313202235 is a deficient number, since it is larger than the sum of its proper divisors (29102762165).

145313202235 is an equidigital number, since it uses as much as digits as its factorization.

145313202235 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6686957.

The product of its (nonzero) digits is 21600, while the sum is 31.

Adding to 145313202235 its reverse (532202313541), we get a palindrome (677515515776).

The spelling of 145313202235 in words is "one hundred forty-five billion, three hundred thirteen million, two hundred two thousand, two hundred thirty-five".

Divisors: 1 5 4349 21745 6682603 33413015 29062640447 145313202235