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145333025451 = 3288931815823
BaseRepresentation
bin1000011101011010000…
…1011111101010101011
3111220010111201122100100
42013112201133222223
54340120223303301
6150433131040443
713333326222315
oct2072641375253
9456114648310
10145333025451
11566a9782099
12241bb8a0123
1310921712763
147069a1c7b5
153ba900c286
hex21d685faab

145333025451 has 12 divisors (see below), whose sum is σ = 209949202528. Its totient is φ = 96877735344.

The previous prime is 145333025447. The next prime is 145333025507. The reversal of 145333025451 is 154520333541.

145333025451 is a `hidden beast` number, since 145 + 33 + 30 + 2 + 5 + 451 = 666.

It is not a de Polignac number, because 145333025451 - 22 = 145333025447 is a prime.

It is a super-2 number, since 2×1453330254512 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (145333025051) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 827875 + ... + 987948.

Almost surely, 2145333025451 is an apocalyptic number.

145333025451 is a deficient number, since it is larger than the sum of its proper divisors (64616177077).

145333025451 is a wasteful number, since it uses less digits than its factorization.

145333025451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1824722 (or 1824719 counting only the distinct ones).

The product of its (nonzero) digits is 108000, while the sum is 36.

Adding to 145333025451 its reverse (154520333541), we get a palindrome (299853358992).

The spelling of 145333025451 in words is "one hundred forty-five billion, three hundred thirty-three million, twenty-five thousand, four hundred fifty-one".

Divisors: 1 3 9 8893 26679 80037 1815823 5447469 16342407 16148113939 48444341817 145333025451