Base | Representation |
---|---|
bin | 1000011101011010110… |
… | …1101110000011101001 |
3 | 111220010201202110022211 |
4 | 2013112231232003221 |
5 | 4340122033330441 |
6 | 150433323445121 |
7 | 13333365400345 |
oct | 2072655560351 |
9 | 456121673284 |
10 | 145336230121 |
11 | 56700570885 |
12 | 242009867a1 |
13 | 10922295304 |
14 | 706a214625 |
15 | 3ba9441a81 |
hex | 21d6b6e0e9 |
145336230121 has 8 divisors (see below), whose sum is σ = 151687831680. Its totient is φ = 138987348192.
The previous prime is 145336230079. The next prime is 145336230133. The reversal of 145336230121 is 121032633541.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 145336230121 - 211 = 145336228073 is a prime.
It is a super-2 number, since 2×1453362301212 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (145336230191) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 570316 + ... + 784813.
It is an arithmetic number, because the mean of its divisors is an integer number (18960978960).
Almost surely, 2145336230121 is an apocalyptic number.
It is an amenable number.
145336230121 is a deficient number, since it is larger than the sum of its proper divisors (6351601559).
145336230121 is a wasteful number, since it uses less digits than its factorization.
145336230121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1359815.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 145336230121 its reverse (121032633541), we get a palindrome (266368863662).
The spelling of 145336230121 in words is "one hundred forty-five billion, three hundred thirty-six million, two hundred thirty thousand, one hundred twenty-one".
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