Base | Representation |
---|---|
bin | 1000011101011100000… |
… | …0101100101100000011 |
3 | 111220011002010012220220 |
4 | 2013113000230230003 |
5 | 4340124322032001 |
6 | 150434022234123 |
7 | 13333455601164 |
oct | 2072700545403 |
9 | 456132105826 |
10 | 145341205251 |
11 | 56703359760 |
12 | 24202585943 |
13 | 10923317988 |
14 | 706ab4b76b |
15 | 3ba9ac5c36 |
hex | 21d702cb03 |
145341205251 has 16 divisors (see below), whose sum is σ = 220596929280. Its totient is φ = 84255770720.
The previous prime is 145341205241. The next prime is 145341205267. The reversal of 145341205251 is 152502143541.
It is not a de Polignac number, because 145341205251 - 26 = 145341205187 is a prime.
It is a super-2 number, since 2×1453412052512 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is not an unprimeable number, because it can be changed into a prime (145341205241) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 95744436 + ... + 95745953.
It is an arithmetic number, because the mean of its divisors is an integer number (13787308080).
Almost surely, 2145341205251 is an apocalyptic number.
145341205251 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
145341205251 is a deficient number, since it is larger than the sum of its proper divisors (75255724029).
145341205251 is a wasteful number, since it uses less digits than its factorization.
145341205251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 191490426.
The product of its (nonzero) digits is 24000, while the sum is 33.
Adding to 145341205251 its reverse (152502143541), we get a palindrome (297843348792).
The spelling of 145341205251 in words is "one hundred forty-five billion, three hundred forty-one million, two hundred five thousand, two hundred fifty-one".
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