Base | Representation |
---|---|
bin | 1000011101011100000… |
… | …0101110100111100001 |
3 | 111220011002010121202120 |
4 | 2013113000232213201 |
5 | 4340124322310103 |
6 | 150434022334453 |
7 | 13333455633213 |
oct | 2072700564741 |
9 | 456132117676 |
10 | 145341213153 |
11 | 56703364694 |
12 | 2420258a429 |
13 | 1092331b456 |
14 | 706ab505b3 |
15 | 3ba9ac8253 |
hex | 21d702e9e1 |
145341213153 has 4 divisors (see below), whose sum is σ = 193788284208. Its totient is φ = 96894142100.
The previous prime is 145341213133. The next prime is 145341213167. The reversal of 145341213153 is 351312143541.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 145341213153 - 28 = 145341212897 is a prime.
It is a super-2 number, since 2×1453412131532 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (145341213103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24223535523 + ... + 24223535528.
It is an arithmetic number, because the mean of its divisors is an integer number (48447071052).
Almost surely, 2145341213153 is an apocalyptic number.
It is an amenable number.
145341213153 is a deficient number, since it is larger than the sum of its proper divisors (48447071055).
145341213153 is an equidigital number, since it uses as much as digits as its factorization.
145341213153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 48447071054.
The product of its digits is 21600, while the sum is 33.
Adding to 145341213153 its reverse (351312143541), we get a palindrome (496653356694).
The spelling of 145341213153 in words is "one hundred forty-five billion, three hundred forty-one million, two hundred thirteen thousand, one hundred fifty-three".
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