Base | Representation |
---|---|
bin | 11011000100101001… |
… | …10110000110110011 |
3 | 1101111221021210202121 |
4 | 31202110312012303 |
5 | 214231320033210 |
6 | 10402125255111 |
7 | 1023115332253 |
oct | 154224660663 |
9 | 41457253677 |
10 | 14534533555 |
11 | 6189402203 |
12 | 2997704497 |
13 | 14a8295619 |
14 | 9bc49b963 |
15 | 5a101d6da |
hex | 3625361b3 |
14534533555 has 4 divisors (see below), whose sum is σ = 17441440272. Its totient is φ = 11627626840.
The previous prime is 14534533529. The next prime is 14534533609. The reversal of 14534533555 is 55533543541.
14534533555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 14534533555 - 213 = 14534525363 is a prime.
It is a super-2 number, since 2×145345335552 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1453453351 + ... + 1453453360.
It is an arithmetic number, because the mean of its divisors is an integer number (4360360068).
Almost surely, 214534533555 is an apocalyptic number.
14534533555 is a deficient number, since it is larger than the sum of its proper divisors (2906906717).
14534533555 is an equidigital number, since it uses as much as digits as its factorization.
14534533555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2906906716.
The product of its digits is 1350000, while the sum is 43.
The spelling of 14534533555 in words is "fourteen billion, five hundred thirty-four million, five hundred thirty-three thousand, five hundred fifty-five".
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