Base | Representation |
---|---|
bin | 1000011101101010011… |
… | …0000010101100010001 |
3 | 111220022021020200120101 |
4 | 2013122212002230101 |
5 | 4340240214420403 |
6 | 150444011012401 |
7 | 13335115611313 |
oct | 2073246025421 |
9 | 456267220511 |
10 | 145401326353 |
11 | 56734292618 |
12 | 2421a73a101 |
13 | 10932907aaa |
14 | 7074b1b7b3 |
15 | 3baeeee71d |
hex | 21da982b11 |
145401326353 has 4 divisors (see below), whose sum is σ = 153054027760. Its totient is φ = 137748624948.
The previous prime is 145401326339. The next prime is 145401326387. The reversal of 145401326353 is 353623104541.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 145401326353 - 25 = 145401326321 is a prime.
It is a super-2 number, since 2×1454013263532 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (145407326353) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3826350675 + ... + 3826350712.
It is an arithmetic number, because the mean of its divisors is an integer number (38263506940).
Almost surely, 2145401326353 is an apocalyptic number.
It is an amenable number.
145401326353 is a deficient number, since it is larger than the sum of its proper divisors (7652701407).
145401326353 is an equidigital number, since it uses as much as digits as its factorization.
145401326353 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7652701406.
The product of its (nonzero) digits is 129600, while the sum is 37.
The spelling of 145401326353 in words is "one hundred forty-five billion, four hundred one million, three hundred twenty-six thousand, three hundred fifty-three".
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