14540230345 has 4 divisors (see below), whose sum is σ = 17448276420. Its totient is φ = 11632184272.

The previous prime is 14540230303. The next prime is 14540230349. The reversal of 14540230345 is 54303204541.

14540230345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 54303204541 = 11173 ⋅4860217.

It can be written as a sum of positive squares in 2 ways, for example, as 1734139449 + 12806090896 = 41643^2 + 113164^2 .

It is a cyclic number.

It is not a de Polignac number, because 14540230345 - 2⁹ = 14540229833 is a prime.

It is a super-2 number, since 2×14540230345² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (14540230349) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1454023030 + ... + 1454023039.

It is an arithmetic number, because the mean of its divisors is an integer number (4362069105).

Almost surely, 2^14540230345 is an apocalyptic number.

It is an amenable number.

14540230345 is a deficient number, since it is larger than the sum of its proper divisors (2908046075).

14540230345 is an equidigital number, since it uses as much as digits as its factorization.

14540230345 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2908046074.

The product of its (nonzero) digits is 28800, while the sum is 31.

Adding to 14540230345 its reverse (54303204541), we get a palindrome (68843434886).

The spelling of 14540230345 in words is "fourteen billion, five hundred forty million, two hundred thirty thousand, three hundred forty-five".