14540331241 has 4 divisors (see below), whose sum is σ = 14570188672. Its totient is φ = 14510473812.

The previous prime is 14540331227. The next prime is 14540331259. The reversal of 14540331241 is 14213304541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14213304541 = 1933 ⋅7352977.

It is a cyclic number.

It is not a de Polignac number, because 14540331241 - 2²⁹ = 14003460329 is a prime.

It is a super-2 number, since 2×14540331241² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14540331341) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14927985 + ... + 14928958.

It is an arithmetic number, because the mean of its divisors is an integer number (3642547168).

Almost surely, 2^14540331241 is an apocalyptic number.

It is an amenable number.

14540331241 is a deficient number, since it is larger than the sum of its proper divisors (29857431).

14540331241 is an equidigital number, since it uses as much as digits as its factorization.

14540331241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 29857430.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 14540331241 its reverse (14213304541), we get a palindrome (28753635782).

The spelling of 14540331241 in words is "fourteen billion, five hundred forty million, three hundred thirty-one thousand, two hundred forty-one".