14540403121121 has 4 divisors (see below), whose sum is σ = 14540431105200. Its totient is φ = 14540375137044.

The previous prime is 14540403121091. The next prime is 14540403121207. The reversal of 14540403121121 is 12112130404541.

14540403121121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14540403121121 is a prime.

It is a super-2 number, since 2×14540403121121² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14540403121021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13197611 + ... + 14256848.

It is an arithmetic number, because the mean of its divisors is an integer number (3635107776300).

Almost surely, 2^{14540403121121} is an apocalyptic number.

It is an amenable number.

14540403121121 is a deficient number, since it is larger than the sum of its proper divisors (27984079).

14540403121121 is an equidigital number, since it uses as much as digits as its factorization.

14540403121121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 27984078.

The product of its (nonzero) digits is 3840, while the sum is 29.

Adding to 14540403121121 its reverse (12112130404541), we get a palindrome (26652533525662).

The spelling of 14540403121121 in words is "fourteen trillion, five hundred forty billion, four hundred three million, one hundred twenty-one thousand, one hundred twenty-one".