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1454113 = 10191427
BaseRepresentation
bin101100011000000100001
32201212200001
411203000201
5333012423
651100001
715234253
oct5430041
92655601
101454113
11903551
125a1601
133bbb2b
1429bcd3
151dacad
hex163021

1454113 has 4 divisors (see below), whose sum is σ = 1456560. Its totient is φ = 1451668.

The previous prime is 1454099. The next prime is 1454119. The reversal of 1454113 is 3114541.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 1454113 - 25 = 1454081 is a prime.

It is a super-2 number, since 2×14541132 = 4228889233538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1454119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 306 + ... + 1732.

It is an arithmetic number, because the mean of its divisors is an integer number (364140).

21454113 is an apocalyptic number.

It is an amenable number.

1454113 is a deficient number, since it is larger than the sum of its proper divisors (2447).

1454113 is a wasteful number, since it uses less digits than its factorization.

1454113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2446.

The product of its digits is 240, while the sum is 19.

The square root of 1454113 is about 1205.8660787998. The cubic root of 1454113 is about 113.2920370497.

Adding to 1454113 its reverse (3114541), we get a palindrome (4568654).

The spelling of 1454113 in words is "one million, four hundred fifty-four thousand, one hundred thirteen".

Divisors: 1 1019 1427 1454113