Base | Representation |
---|---|
bin | 11011000101100101… |
… | …11100001111111011 |
3 | 1101112111010122002120 |
4 | 31202302330033323 |
5 | 214240330014120 |
6 | 10403010332323 |
7 | 1023242361540 |
oct | 154262741773 |
9 | 41474118076 |
10 | 14542423035 |
11 | 6192900738 |
12 | 299a28a0a3 |
13 | 14a9ac865a |
14 | 9bd552bc7 |
15 | 5a1a7b140 |
hex | 362cbc3fb |
14542423035 has 16 divisors (see below), whose sum is σ = 26591859456. Its totient is φ = 6647964768.
The previous prime is 14542423013. The next prime is 14542423117. The reversal of 14542423035 is 53032424541.
It is not a de Polignac number, because 14542423035 - 26 = 14542422971 is a prime.
It is a super-2 number, since 2×145424230352 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14542422987 and 14542423005.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69249529 + ... + 69249738.
It is an arithmetic number, because the mean of its divisors is an integer number (1661991216).
Almost surely, 214542423035 is an apocalyptic number.
14542423035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
14542423035 is a deficient number, since it is larger than the sum of its proper divisors (12049436421).
14542423035 is a wasteful number, since it uses less digits than its factorization.
14542423035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 138499282.
The product of its (nonzero) digits is 57600, while the sum is 33.
Adding to 14542423035 its reverse (53032424541), we get a palindrome (67574847576).
The spelling of 14542423035 in words is "fourteen billion, five hundred forty-two million, four hundred twenty-three thousand, thirty-five".
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