Base | Representation |
---|---|
bin | 100001000101010110010110… |
… | …000110110000011001110011 |
3 | 201002011221222222122012002012 |
4 | 201011112112012300121303 |
5 | 123032410400103040430 |
6 | 1233243114003513135 |
7 | 42435153042523112 |
oct | 4105262606603163 |
9 | 632157888565065 |
10 | 145503125440115 |
11 | 423a8590063663 |
12 | 1439b5923887ab |
13 | 6325b692b7081 |
14 | 27d0562dd3c79 |
15 | 11c4d0be12695 |
hex | 8455961b0673 |
145503125440115 has 8 divisors (see below), whose sum is σ = 174604042458720. Its totient is φ = 116402305731712.
The previous prime is 145503125440111. The next prime is 145503125440117. The reversal of 145503125440115 is 511044521305541.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 145503125440115 - 22 = 145503125440111 is a prime.
It is not an unprimeable number, because it can be changed into a prime (145503125440111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20996534 + ... + 27052923.
It is an arithmetic number, because the mean of its divisors is an integer number (21825505307340).
Almost surely, 2145503125440115 is an apocalyptic number.
145503125440115 is a deficient number, since it is larger than the sum of its proper divisors (29100917018605).
145503125440115 is an equidigital number, since it uses as much as digits as its factorization.
145503125440115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 48655101.
The product of its (nonzero) digits is 240000, while the sum is 41.
Adding to 145503125440115 its reverse (511044521305541), we get a palindrome (656547646745656).
The spelling of 145503125440115 in words is "one hundred forty-five trillion, five hundred three billion, one hundred twenty-five million, four hundred forty thousand, one hundred fifteen".
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