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14552350304131 = 89163509553979
BaseRepresentation
bin1101001111000011101110…
…1010111010011110000011
31220112012011022110122210001
43103300323222322132003
53401411203134213011
650541131335020431
73031241543436343
oct323607352723603
956465138418701
1014552350304131
114700687405442
12177041480a717
13817385a4a533
143844a21c6d23
151a38178d27c1
hexd3c3baba783

14552350304131 has 4 divisors (see below), whose sum is σ = 14715859858200. Its totient is φ = 14388840750064.

The previous prime is 14552350304099. The next prime is 14552350304143. The reversal of 14552350304131 is 13140305325541.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14552350304131 - 25 = 14552350304099 is a prime.

It is a super-2 number, since 2×145523503041312 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14552350304231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 81754776901 + ... + 81754777078.

It is an arithmetic number, because the mean of its divisors is an integer number (3678964964550).

Almost surely, 214552350304131 is an apocalyptic number.

14552350304131 is a deficient number, since it is larger than the sum of its proper divisors (163509554069).

14552350304131 is an equidigital number, since it uses as much as digits as its factorization.

14552350304131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 163509554068.

The product of its (nonzero) digits is 108000, while the sum is 37.

Adding to 14552350304131 its reverse (13140305325541), we get a palindrome (27692655629672).

The spelling of 14552350304131 in words is "fourteen trillion, five hundred fifty-two billion, three hundred fifty million, three hundred four thousand, one hundred thirty-one".

Divisors: 1 89 163509553979 14552350304131