Base | Representation |
---|---|
bin | 1000011110011010100… |
… | …1110110010111011011 |
3 | 111220211100221211212010 |
4 | 2013212221312113123 |
5 | 4341144013313120 |
6 | 150520035321003 |
7 | 13343123420223 |
oct | 2074651662733 |
9 | 456740854763 |
10 | 145603651035 |
11 | 568285130a7 |
12 | 24276450163 |
13 | 109657c723b |
14 | 7093947083 |
15 | 3bc2b677e0 |
hex | 21e6a765db |
145603651035 has 16 divisors (see below), whose sum is σ = 232971208704. Its totient is φ = 77653491552.
The previous prime is 145603651021. The next prime is 145603651049. The reversal of 145603651035 is 530156306541.
It is an interprime number because it is at equal distance from previous prime (145603651021) and next prime (145603651049).
It is not a de Polignac number, because 145603651035 - 25 = 145603651003 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 145603650984 and 145603651002.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 801804 + ... + 966486.
It is an arithmetic number, because the mean of its divisors is an integer number (14560700544).
Almost surely, 2145603651035 is an apocalyptic number.
145603651035 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
145603651035 is a deficient number, since it is larger than the sum of its proper divisors (87367557669).
145603651035 is a wasteful number, since it uses less digits than its factorization.
145603651035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 223634.
The product of its (nonzero) digits is 162000, while the sum is 39.
Adding to 145603651035 its reverse (530156306541), we get a palindrome (675759957576).
The spelling of 145603651035 in words is "one hundred forty-five billion, six hundred three million, six hundred fifty-one thousand, thirty-five".
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