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146116114003 = 211691690233
BaseRepresentation
bin1000100000010100110…
…0101111011001010011
3111222011002020122220001
42020011030233121103
54343221211122003
6151042543230431
713361615322316
oct2100514573123
9458132218801
10146116114003
1156a70812112
1224399ba8417
1310a17a23c72
147101a2497d
153c02b4361d
hex220532f653

146116114003 has 4 divisors (see below), whose sum is σ = 146117015928. Its totient is φ = 146115212080.

The previous prime is 146116113989. The next prime is 146116114043. The reversal of 146116114003 is 300411611641.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 146116114003 - 29 = 146116113491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (146116114043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133426 + ... + 556807.

It is an arithmetic number, because the mean of its divisors is an integer number (36529253982).

Almost surely, 2146116114003 is an apocalyptic number.

146116114003 is a deficient number, since it is larger than the sum of its proper divisors (901925).

146116114003 is an equidigital number, since it uses as much as digits as its factorization.

146116114003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 901924.

The product of its (nonzero) digits is 1728, while the sum is 28.

Adding to 146116114003 its reverse (300411611641), we get a palindrome (446527725644).

The spelling of 146116114003 in words is "one hundred forty-six billion, one hundred sixteen million, one hundred fourteen thousand, three".

Divisors: 1 211691 690233 146116114003