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14643364145 = 52928672829
BaseRepresentation
bin11011010001101000…
…00000000100110001
31101210112001222021012
431220310000010301
5214442200123040
610421014040305
71025606353514
oct155064000461
941715058235
1014643364145
116234885243
122a08049095
1314c49ab617
149ccb0ad7b
155aa869865
hex368d00131

14643364145 has 4 divisors (see below), whose sum is σ = 17572036980. Its totient is φ = 11714691312.

The previous prime is 14643364123. The next prime is 14643364159. The reversal of 14643364145 is 54146334641.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3086469136 + 11556895009 = 55556^2 + 107503^2 .

It is a cyclic number.

It is not a de Polignac number, because 14643364145 - 224 = 14626586929 is a prime.

It is a super-2 number, since 2×146433641452 (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1464336410 + ... + 1464336419.

It is an arithmetic number, because the mean of its divisors is an integer number (4393009245).

Almost surely, 214643364145 is an apocalyptic number.

It is an amenable number.

14643364145 is a deficient number, since it is larger than the sum of its proper divisors (2928672835).

14643364145 is an equidigital number, since it uses as much as digits as its factorization.

14643364145 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2928672834.

The product of its digits is 414720, while the sum is 41.

Adding to 14643364145 its reverse (54146334641), we get a palindrome (68789698786).

The spelling of 14643364145 in words is "fourteen billion, six hundred forty-three million, three hundred sixty-four thousand, one hundred forty-five".

Divisors: 1 5 2928672829 14643364145