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14644454217 = 34881484739
BaseRepresentation
bin11011010001110000…
…01010001101001001
31101210121010100120020
431220320022031021
5214442440013332
610421053251053
71025621543541
oct155070121511
941717110506
1014644454217
11623545a228
122a08493a89
1314c4ca0833
149ccd12321
155aa9d282c
hex368e0a349

14644454217 has 4 divisors (see below), whose sum is σ = 19525938960. Its totient is φ = 9762969476.

The previous prime is 14644454203. The next prime is 14644454309. The reversal of 14644454217 is 71245444641.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14644454217 - 210 = 14644453193 is a prime.

It is not an unprimeable number, because it can be changed into a prime (14644454417) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2440742367 + ... + 2440742372.

It is an arithmetic number, because the mean of its divisors is an integer number (4881484740).

Almost surely, 214644454217 is an apocalyptic number.

It is an amenable number.

14644454217 is a deficient number, since it is larger than the sum of its proper divisors (4881484743).

14644454217 is an equidigital number, since it uses as much as digits as its factorization.

14644454217 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4881484742.

The product of its digits is 430080, while the sum is 42.

Adding to 14644454217 its reverse (71245444641), we get a palindrome (85889898858).

It can be divided in two parts, 146444 and 54217, that added together give a triangular number (200661 = T633).

The spelling of 14644454217 in words is "fourteen billion, six hundred forty-four million, four hundred fifty-four thousand, two hundred seventeen".

Divisors: 1 3 4881484739 14644454217