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146714212241 = 312314697711
BaseRepresentation
bin1000100010100011011…
…0010011011110010001
3112000200202200012102122
42020220312103132101
54400432314242431
6151222150424025
713412500141052
oct2105066233621
9460622605378
10146714212241
1157248391183
1224526362015
1310ab190504c
14715b234729
153c3a3d7a7b
hex2228d93791

146714212241 has 4 divisors (see below), whose sum is σ = 146718941184. Its totient is φ = 146709483300.

The previous prime is 146714212231. The next prime is 146714212279. The reversal of 146714212241 is 142212417641.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 146714212241 - 214 = 146714195857 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (146714212231) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2317625 + ... + 2380086.

It is an arithmetic number, because the mean of its divisors is an integer number (36679735296).

Almost surely, 2146714212241 is an apocalyptic number.

It is an amenable number.

146714212241 is a deficient number, since it is larger than the sum of its proper divisors (4728943).

146714212241 is an equidigital number, since it uses as much as digits as its factorization.

146714212241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4728942.

The product of its digits is 21504, while the sum is 35.

Adding to 146714212241 its reverse (142212417641), we get a palindrome (288926629882).

The spelling of 146714212241 in words is "one hundred forty-six billion, seven hundred fourteen million, two hundred twelve thousand, two hundred forty-one".

Divisors: 1 31231 4697711 146714212241