14701010001 has 4 divisors (see below), whose sum is σ = 19601346672. Its totient is φ = 9800673332.

The previous prime is 14701009987. The next prime is 14701010003. The reversal of 14701010001 is 10001010741.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 14701010001 - 2⁵ = 14701009969 is a prime.

It is a super-3 number, since 3×14701010001³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (14701010003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2450168331 + ... + 2450168336.

It is an arithmetic number, because the mean of its divisors is an integer number (4900336668).

Almost surely, 2^14701010001 is an apocalyptic number.

It is an amenable number.

14701010001 is a deficient number, since it is larger than the sum of its proper divisors (4900336671).

14701010001 is an equidigital number, since it uses as much as digits as its factorization.

14701010001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4900336670.

The product of its (nonzero) digits is 28, while the sum is 15.

Adding to 14701010001 its reverse (10001010741), we get a palindrome (24702020742).

The spelling of 14701010001 in words is "fourteen billion, seven hundred one million, ten thousand, one".