Base | Representation |
---|---|
bin | 10101011010001000010… |
… | …000111000011101110001 |
3 | 12012122100000101102121121 |
4 | 111122020100320131301 |
5 | 143100421211122233 |
6 | 3043502134222241 |
7 | 211200560452432 |
oct | 25321020703561 |
9 | 5178300342547 |
10 | 1471164942193 |
11 | 517a10290701 |
12 | 1b91561b4981 |
13 | a89654bc81b |
14 | 512c1c27489 |
15 | 28405b8392d |
hex | 15688438771 |
1471164942193 has 4 divisors (see below), whose sum is σ = 1472118388288. Its totient is φ = 1470211496100.
The previous prime is 1471164942187. The next prime is 1471164942217. The reversal of 1471164942193 is 3912494611741.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1471164942193 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1471164942193.
It is not an unprimeable number, because it can be changed into a prime (1471164942103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 476720733 + ... + 476723818.
It is an arithmetic number, because the mean of its divisors is an integer number (368029597072).
Almost surely, 21471164942193 is an apocalyptic number.
It is an amenable number.
1471164942193 is a deficient number, since it is larger than the sum of its proper divisors (953446095).
1471164942193 is an equidigital number, since it uses as much as digits as its factorization.
1471164942193 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 953446094.
The product of its digits is 1306368, while the sum is 52.
The spelling of 1471164942193 in words is "one trillion, four hundred seventy-one billion, one hundred sixty-four million, nine hundred forty-two thousand, one hundred ninety-three".
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