Base | Representation |
---|---|
bin | 11011100101001011… |
… | …10011001011101001 |
3 | 1102012221202112122112 |
4 | 31302211303023221 |
5 | 220311144212411 |
6 | 10445154132105 |
7 | 1032640636460 |
oct | 156245631351 |
9 | 42187675575 |
10 | 14807413481 |
11 | 6309442a03 |
12 | 2a52b81035 |
13 | 151c989233 |
14 | a068119d7 |
15 | 5b9e71b8b |
hex | 3729732e9 |
14807413481 has 4 divisors (see below), whose sum is σ = 16922758272. Its totient is φ = 12692068692.
The previous prime is 14807413451. The next prime is 14807413499. The reversal of 14807413481 is 18431470841.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-14807413481 is a prime.
It is a super-2 number, since 2×148074134812 (a number of 21 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (14807413451) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1057672385 + ... + 1057672398.
It is an arithmetic number, because the mean of its divisors is an integer number (4230689568).
Almost surely, 214807413481 is an apocalyptic number.
It is an amenable number.
14807413481 is a deficient number, since it is larger than the sum of its proper divisors (2115344791).
14807413481 is an equidigital number, since it uses as much as digits as its factorization.
14807413481 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2115344790.
The product of its (nonzero) digits is 86016, while the sum is 41.
The spelling of 14807413481 in words is "fourteen billion, eight hundred seven million, four hundred thirteen thousand, four hundred eighty-one".
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