1482312132841 has 4 divisors (see below), whose sum is σ = 1482315046992. Its totient is φ = 1482309218692.

The previous prime is 1482312132709. The next prime is 1482312132859.

1482312132841 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1482312132841 - 2²⁵ = 1482278578409 is a prime.

It is a super-3 number, since 3×1482312132841³ (a number of 37 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1482312132794 and 1482312132803.

It is not an unprimeable number, because it can be changed into a prime (1482312132541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 472171 + ... + 1785376.

It is an arithmetic number, because the mean of its divisors is an integer number (370578761748).

Almost surely, 2^{1482312132841} is an apocalyptic number.

It is an amenable number.

1482312132841 is a deficient number, since it is larger than the sum of its proper divisors (2914151).

1482312132841 is an equidigital number, since it uses as much as digits as its factorization.

1482312132841 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2914150.

The product of its digits is 73728, while the sum is 40.

The spelling of 1482312132841 in words is "one trillion, four hundred eighty-two billion, three hundred twelve million, one hundred thirty-two thousand, eight hundred forty-one".