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14834035 = 52966807
BaseRepresentation
bin111000100101…
…100101110011
31000220122110201
4320211211303
512244142120
61245540031
7240041626
oct70454563
930818421
1014834035
118412037
124b74617
1330c4c48
141d81dbd
15148040a
hexe25973

14834035 has 4 divisors (see below), whose sum is σ = 17800848. Its totient is φ = 11867224.

The previous prime is 14834033. The next prime is 14834063. The reversal of 14834035 is 53043841.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14834035 - 21 = 14834033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14833994 and 14834012.

It is not an unprimeable number, because it can be changed into a prime (14834033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1483399 + ... + 1483408.

It is an arithmetic number, because the mean of its divisors is an integer number (4450212).

Almost surely, 214834035 is an apocalyptic number.

14834035 is a deficient number, since it is larger than the sum of its proper divisors (2966813).

14834035 is an equidigital number, since it uses as much as digits as its factorization.

14834035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2966812.

The product of its (nonzero) digits is 5760, while the sum is 28.

The square root of 14834035 is about 3851.4977606121. The cubic root of 14834035 is about 245.7082656622.

Adding to 14834035 its reverse (53043841), we get a palindrome (67877876).

The spelling of 14834035 in words is "fourteen million, eight hundred thirty-four thousand, thirty-five".

Divisors: 1 5 2966807 14834035