14840113 has 4 divisors (see below), whose sum is σ = 14926068. Its totient is φ = 14754160.

The previous prime is 14840107. The next prime is 14840123. The reversal of 14840113 is 31104841.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31104841 = 229 ⋅135829.

It can be written as a sum of positive squares in 2 ways, for example, as 13601344 + 1238769 = 3688^2 + 1113^2 .

It is a cyclic number.

It is not a de Polignac number, because 14840113 - 2¹⁷ = 14709041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (14840123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 42718 + ... + 43063.

It is an arithmetic number, because the mean of its divisors is an integer number (3731517).

Almost surely, 2^14840113 is an apocalyptic number.

It is an amenable number.

14840113 is a deficient number, since it is larger than the sum of its proper divisors (85955).

14840113 is an equidigital number, since it uses as much as digits as its factorization.

14840113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 85954.

The product of its (nonzero) digits is 384, while the sum is 22.

The square root of 14840113 is about 3852.2867234929. The cubic root of 14840113 is about 245.7418193765.

Adding to 14840113 its reverse (31104841), we get a palindrome (45944954).

The spelling of 14840113 in words is "fourteen million, eight hundred forty thousand, one hundred thirteen".