1490427389403 has 6 divisors (see below), whose sum is σ = 2152839562484. Its totient is φ = 993618259596.

The previous prime is 1490427389401. The next prime is 1490427389461. The reversal of 1490427389403 is 3049837240941.

1490427389403 is a `hidden beast` number, since 1 + 4 + 90 + 4 + 2 + 73 + 89 + 403 = 666.

It is not a de Polignac number, because 1490427389403 - 2¹ = 1490427389401 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1490427389403.

It is not an unprimeable number, because it can be changed into a prime (1490427389401) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 82801521625 + ... + 82801521642.

Almost surely, 2^{1490427389403} is an apocalyptic number.

1490427389403 is a deficient number, since it is larger than the sum of its proper divisors (662412173081).

1490427389403 is a wasteful number, since it uses less digits than its factorization.

1490427389403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 165603043273 (or 165603043270 counting only the distinct ones).

The product of its (nonzero) digits is 5225472, while the sum is 54.

The spelling of 1490427389403 in words is "one trillion, four hundred ninety billion, four hundred twenty-seven million, three hundred eighty-nine thousand, four hundred three".