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14926889251 = 29514720319
BaseRepresentation
bin11011110011011011…
…00100000100100011
31102112021120112121001
431321231210010203
5221032240424001
610505103012431
71035621315361
oct157155440443
942467515531
1014926889251
11636a92690a
122a86b9a117
13153b65b661
14a18632631
155c56c2001
hex379b64123

14926889251 has 4 divisors (see below), whose sum is σ = 15441609600. Its totient is φ = 14412168904.

The previous prime is 14926889249. The next prime is 14926889293. The reversal of 14926889251 is 15298862941.

14926889251 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14926889251 - 21 = 14926889249 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14926889192 and 14926889201.

It is not an unprimeable number, because it can be changed into a prime (14926889851) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 257360131 + ... + 257360188.

It is an arithmetic number, because the mean of its divisors is an integer number (3860402400).

Almost surely, 214926889251 is an apocalyptic number.

14926889251 is a deficient number, since it is larger than the sum of its proper divisors (514720349).

14926889251 is an equidigital number, since it uses as much as digits as its factorization.

14926889251 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 514720348.

The product of its digits is 2488320, while the sum is 55.

The spelling of 14926889251 in words is "fourteen billion, nine hundred twenty-six million, eight hundred eighty-nine thousand, two hundred fifty-one".

Divisors: 1 29 514720319 14926889251