Base | Representation |
---|---|
bin | 11011110011100101… |
… | …01011101011011011 |
3 | 1102112101002201022022 |
4 | 31321302223223123 |
5 | 221033111344011 |
6 | 10505151445055 |
7 | 1035635604512 |
oct | 157162535333 |
9 | 42471081268 |
10 | 14928231131 |
11 | 6370663000 |
12 | 2a8752678b |
13 | 153ba0b378 |
14 | a188a1679 |
15 | 5c58898db |
hex | 379cabadb |
14928231131 has 36 divisors (see below), whose sum is σ = 17531618136. Its totient is φ = 12707981440.
The previous prime is 14928231119. The next prime is 14928231137. The reversal of 14928231131 is 13113282941.
It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.
It is not a de Polignac number, because 14928231131 - 26 = 14928231067 is a prime.
It is a super-2 number, since 2×149282311312 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 14928231091 and 14928231100.
It is not an unprimeable number, because it can be changed into a prime (14928231137) by changing a digit.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 75777725 + ... + 75777921.
Almost surely, 214928231131 is an apocalyptic number.
14928231131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14928231131 is a deficient number, since it is larger than the sum of its proper divisors (2603387005).
14928231131 is an frugal number, since it uses more digits than its factorization.
14928231131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 461 (or 225 counting only the distinct ones).
The product of its digits is 10368, while the sum is 35.
The spelling of 14928231131 in words is "fourteen billion, nine hundred twenty-eight million, two hundred thirty-one thousand, one hundred thirty-one".
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