Base | Representation |
---|---|
bin | 11011110100011010… |
… | …00000000111100001 |
3 | 1102112212002020120221 |
4 | 31322031000013201 |
5 | 221041343134333 |
6 | 10505555403041 |
7 | 1036051341535 |
oct | 157215000741 |
9 | 42485066527 |
10 | 14935130593 |
11 | 6374545739 |
12 | 2a898b3481 |
13 | 15402858a6 |
14 | a19779bc5 |
15 | 5c629dd2d |
hex | 37a3401e1 |
14935130593 has 4 divisors (see below), whose sum is σ = 14990242048. Its totient is φ = 14880019140.
The previous prime is 14935130543. The next prime is 14935130621. The reversal of 14935130593 is 39503153941.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 39503153941 = 151 ⋅261610291.
It is a cyclic number.
It is not a de Polignac number, because 14935130593 - 221 = 14933033441 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14935130503) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 27555321 + ... + 27555862.
It is an arithmetic number, because the mean of its divisors is an integer number (3747560512).
Almost surely, 214935130593 is an apocalyptic number.
It is an amenable number.
14935130593 is a deficient number, since it is larger than the sum of its proper divisors (55111455).
14935130593 is an equidigital number, since it uses as much as digits as its factorization.
14935130593 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 55111454.
The product of its (nonzero) digits is 218700, while the sum is 43.
The spelling of 14935130593 in words is "fourteen billion, nine hundred thirty-five million, one hundred thirty thousand, five hundred ninety-three".
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