Base | Representation |
---|---|
bin | 11011110100110000… |
… | …11000101111001001 |
3 | 1102120001200212110011 |
4 | 31322120120233021 |
5 | 221043124140032 |
6 | 10510143351521 |
7 | 1036115611510 |
oct | 157230305711 |
9 | 42501625404 |
10 | 14938115017 |
11 | 63761a3a01 |
12 | 2a8a8b25a1 |
13 | 1540a8c117 |
14 | a19d15677 |
15 | 5c668d247 |
hex | 37a618bc9 |
14938115017 has 4 divisors (see below), whose sum is σ = 17072131456. Its totient is φ = 12804098580.
The previous prime is 14938115011. The next prime is 14938115041. The reversal of 14938115017 is 71051183941.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a de Polignac number, because none of the positive numbers 2k-14938115017 is a prime.
It is a super-2 number, since 2×149381150172 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (14938115011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1067008209 + ... + 1067008222.
It is an arithmetic number, because the mean of its divisors is an integer number (4268032864).
Almost surely, 214938115017 is an apocalyptic number.
It is an amenable number.
14938115017 is a deficient number, since it is larger than the sum of its proper divisors (2134016439).
14938115017 is an equidigital number, since it uses as much as digits as its factorization.
14938115017 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2134016438.
The product of its (nonzero) digits is 30240, while the sum is 40.
Adding to 14938115017 its reverse (71051183941), we get a palindrome (85989298958).
The spelling of 14938115017 in words is "fourteen billion, nine hundred thirty-eight million, one hundred fifteen thousand, seventeen".
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