Base | Representation |
---|---|
bin | 1000101100100011111… |
… | …1011110110100001011 |
3 | 112021122000021202200220 |
4 | 2023020333132310023 |
5 | 4421433122110210 |
6 | 152344525201123 |
7 | 13536203212362 |
oct | 2131077366413 |
9 | 467560252626 |
10 | 149400972555 |
11 | 583a6a54a4a |
12 | 24b561001a3 |
13 | 1111c434453 |
14 | 7333dbc7d9 |
15 | 3d46204c70 |
hex | 22c8fded0b |
149400972555 has 8 divisors (see below), whose sum is σ = 239041556112. Its totient is φ = 79680518688.
The previous prime is 149400972547. The next prime is 149400972607. The reversal of 149400972555 is 555279004941.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 149400972555 - 23 = 149400972547 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 149400972498 and 149400972507.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4980032404 + ... + 4980032433.
It is an arithmetic number, because the mean of its divisors is an integer number (29880194514).
Almost surely, 2149400972555 is an apocalyptic number.
149400972555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
149400972555 is a deficient number, since it is larger than the sum of its proper divisors (89640583557).
149400972555 is an equidigital number, since it uses as much as digits as its factorization.
149400972555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9960064845.
The product of its (nonzero) digits is 2268000, while the sum is 51.
The spelling of 149400972555 in words is "one hundred forty-nine billion, four hundred million, nine hundred seventy-two thousand, five hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.077 sec. • engine limits •