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14955159457 = 72136451351
BaseRepresentation
bin11011110110110010…
…11001111110100001
31102121020202211000201
431323121121332201
5221112010100312
610511552545201
71036413520660
oct157331317641
942536684021
1014955159457
116384885717
122a94552201
1315444791a4
14a1c2b0dd7
155c7e08557
hex37b659fa1

14955159457 has 4 divisors (see below), whose sum is σ = 17091610816. Its totient is φ = 12818708100.

The previous prime is 14955159449. The next prime is 14955159497. The reversal of 14955159457 is 75495155941.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 75495155941 = 312435327611.

It is a cyclic number.

It is not a de Polignac number, because 14955159457 - 23 = 14955159449 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14955159398 and 14955159407.

It is not an unprimeable number, because it can be changed into a prime (14955159497) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1068225669 + ... + 1068225682.

It is an arithmetic number, because the mean of its divisors is an integer number (4272902704).

Almost surely, 214955159457 is an apocalyptic number.

It is an amenable number.

14955159457 is a deficient number, since it is larger than the sum of its proper divisors (2136451359).

14955159457 is an equidigital number, since it uses as much as digits as its factorization.

14955159457 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2136451358.

The product of its digits is 5670000, while the sum is 55.

The spelling of 14955159457 in words is "fourteen billion, nine hundred fifty-five million, one hundred fifty-nine thousand, four hundred fifty-seven".

Divisors: 1 7 2136451351 14955159457