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150005130001 = 787190603723
BaseRepresentation
bin1000101110110100000…
…0001010001100010001
3112100012010010010220121
42023231000022030101
54424202303130001
6152524510310241
713560160365346
oct2135500121421
9470163103817
10150005130001
1158686a92421
12250a44b8381
13111b765746c
1473903287cd
153d7e2946a1
hex22ed00a311

150005130001 has 4 divisors (see below), whose sum is σ = 150195734512. Its totient is φ = 149814525492.

The previous prime is 150005129999. The next prime is 150005130013. The reversal of 150005130001 is 100031500051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 100031500051 = 714290214293.

It is a cyclic number.

It is not a de Polignac number, because 150005130001 - 21 = 150005129999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150005130061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95301075 + ... + 95302648.

It is an arithmetic number, because the mean of its divisors is an integer number (37548933628).

Almost surely, 2150005130001 is an apocalyptic number.

It is an amenable number.

150005130001 is a deficient number, since it is larger than the sum of its proper divisors (190604511).

150005130001 is an equidigital number, since it uses as much as digits as its factorization.

150005130001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 190604510.

The product of its (nonzero) digits is 75, while the sum is 16.

Adding to 150005130001 its reverse (100031500051), we get a palindrome (250036630052).

The spelling of 150005130001 in words is "one hundred fifty billion, five million, one hundred thirty thousand, one".

Divisors: 1 787 190603723 150005130001