Base | Representation |
---|---|
bin | 11011111100010000… |
… | …10001100110011001 |
3 | 1102201110000202220101 |
4 | 31332020101212121 |
5 | 221210224002340 |
6 | 10520311255401 |
7 | 1040511253612 |
oct | 157610214631 |
9 | 42643022811 |
10 | 15001000345 |
11 | 63a8745651 |
12 | 2aa797a561 |
13 | 1550b09486 |
14 | a24404c09 |
15 | 5cbe60c9a |
hex | 37e211999 |
15001000345 has 16 divisors (see below), whose sum is σ = 19328554368. Its totient is φ = 11135783680.
The previous prime is 15001000331. The next prime is 15001000349. The reversal of 15001000345 is 54300010051.
15001000345 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 15001000345 - 211 = 15000998297 is a prime.
It is a super-2 number, since 2×150010003452 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15001000349) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1236799 + ... + 1248868.
It is an arithmetic number, because the mean of its divisors is an integer number (1208034648).
Almost surely, 215001000345 is an apocalyptic number.
It is an amenable number.
15001000345 is a deficient number, since it is larger than the sum of its proper divisors (4327554023).
15001000345 is a wasteful number, since it uses less digits than its factorization.
15001000345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2485760.
The product of its (nonzero) digits is 300, while the sum is 19.
Adding to 15001000345 its reverse (54300010051), we get a palindrome (69301010396).
The spelling of 15001000345 in words is "fifteen billion, one million, three hundred forty-five", and thus it is an aban number.
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