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150010131 = 350003377
BaseRepresentation
bin10001111000011…
…11100100010011
3101110021022012210
420330033210103
5301400311011
622515123203
73501031215
oct1074174423
9343238183
10150010131
1177749917
12422a3503
13251036bb
1415ccc5b5
15d2826a6
hex8f0f913

150010131 has 4 divisors (see below), whose sum is σ = 200013512. Its totient is φ = 100006752.

The previous prime is 150010121. The next prime is 150010139. The reversal of 150010131 is 131010051.

150010131 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 150010131 - 26 = 150010067 is a prime.

It is a super-2 number, since 2×1500101312 = 45006078805274322, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150010139) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25001686 + ... + 25001691.

It is an arithmetic number, because the mean of its divisors is an integer number (50003378).

Almost surely, 2150010131 is an apocalyptic number.

150010131 is a deficient number, since it is larger than the sum of its proper divisors (50003381).

150010131 is an equidigital number, since it uses as much as digits as its factorization.

150010131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50003380.

The product of its (nonzero) digits is 15, while the sum is 12.

The square root of 150010131 is about 12247.8623032756. The cubic root of 150010131 is about 531.3412463153.

Adding to 150010131 its reverse (131010051), we get a palindrome (281020182).

The spelling of 150010131 in words is "one hundred fifty million, ten thousand, one hundred thirty-one".

Divisors: 1 3 50003377 150010131