Base | Representation |
---|---|
bin | 11011111100011100… |
… | …00100101001001011 |
3 | 1102201112212222200001 |
4 | 31332032010221023 |
5 | 221211121121024 |
6 | 10520404023431 |
7 | 1040530213525 |
oct | 157616045113 |
9 | 42645788601 |
10 | 15002520139 |
11 | 63a9593482 |
12 | 2aa8391b77 |
13 | 155121c169 |
14 | a246bca15 |
15 | 5cc161244 |
hex | 37e384a4b |
15002520139 has 4 divisors (see below), whose sum is σ = 15002944024. Its totient is φ = 15002096256.
The previous prime is 15002520107. The next prime is 15002520167. The reversal of 15002520139 is 93102520051.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 93102520051 = 73 ⋅1275376987.
It is a cyclic number.
It is not a de Polignac number, because 15002520139 - 25 = 15002520107 is a prime.
It is a super-2 number, since 2×150025201392 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15002526139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 153477 + ... + 231430.
It is an arithmetic number, because the mean of its divisors is an integer number (3750736006).
Almost surely, 215002520139 is an apocalyptic number.
15002520139 is a deficient number, since it is larger than the sum of its proper divisors (423885).
15002520139 is an equidigital number, since it uses as much as digits as its factorization.
15002520139 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 423884.
The product of its (nonzero) digits is 2700, while the sum is 28.
The spelling of 15002520139 in words is "fifteen billion, two million, five hundred twenty thousand, one hundred thirty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •