150043122223121 has 4 divisors (see below), whose sum is σ = 150075189576000. Its totient is φ = 150011054870244.

The previous prime is 150043122223097. The next prime is 150043122223199. The reversal of 150043122223121 is 121322221340051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-150043122223121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150043122213121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16033669421 + ... + 16033678778.

It is an arithmetic number, because the mean of its divisors is an integer number (37518797394000).

Almost surely, 2^{150043122223121} is an apocalyptic number.

It is an amenable number.

150043122223121 is a deficient number, since it is larger than the sum of its proper divisors (32067352879).

150043122223121 is an equidigital number, since it uses as much as digits as its factorization.

150043122223121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 32067352878.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 150043122223121 its reverse (121322221340051), we get a palindrome (271365343563172).

The spelling of 150043122223121 in words is "one hundred fifty trillion, forty-three billion, one hundred twenty-two million, two hundred twenty-three thousand, one hundred twenty-one".