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150113112240011 = 467321441353833
BaseRepresentation
bin100010001000011011101110…
…101110110010111110001011
3201200111200011220002221111012
4202020123232232302332023
5124133423123213140021
61251133002311554135
743422212601011024
oct4210335656627613
9650450156087435
10150113112240011
1143915682467358
1214a04b1568b94b
13659b7b4a8814b
14290d728aa1c4b
151254bbe88c35b
hex8886eebb2f8b

150113112240011 has 4 divisors (see below), whose sum is σ = 150434553594312. Its totient is φ = 149791670885712.

The previous prime is 150113112240001. The next prime is 150113112240023. The reversal of 150113112240011 is 110042211311051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 150113112240011 - 246 = 79744368062347 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (150113112240001) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 160720676450 + ... + 160720677383.

It is an arithmetic number, because the mean of its divisors is an integer number (37608638398578).

Almost surely, 2150113112240011 is an apocalyptic number.

150113112240011 is a deficient number, since it is larger than the sum of its proper divisors (321441354301).

150113112240011 is an equidigital number, since it uses as much as digits as its factorization.

150113112240011 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 321441354300.

The product of its (nonzero) digits is 240, while the sum is 23.

Adding to 150113112240011 its reverse (110042211311051), we get a palindrome (260155323551062).

The spelling of 150113112240011 in words is "one hundred fifty trillion, one hundred thirteen billion, one hundred twelve million, two hundred forty thousand, eleven".

Divisors: 1 467 321441353833 150113112240011