15013501145113 has 4 divisors (see below), whose sum is σ = 15014520337168. Its totient is φ = 15012481953060.

The previous prime is 15013501145107. The next prime is 15013501145129. The reversal of 15013501145113 is 31154110531051.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15013501145113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (15013501145183) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 509573931 + ... + 509603392.

It is an arithmetic number, because the mean of its divisors is an integer number (3753630084292).

Almost surely, 2^{15013501145113} is an apocalyptic number.

It is an amenable number.

15013501145113 is a deficient number, since it is larger than the sum of its proper divisors (1019192055).

15013501145113 is a wasteful number, since it uses less digits than its factorization.

15013501145113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1019192054.

The product of its (nonzero) digits is 4500, while the sum is 31.

Adding to 15013501145113 its reverse (31154110531051), we get a palindrome (46167611676164).

The spelling of 15013501145113 in words is "fifteen trillion, thirteen billion, five hundred one million, one hundred forty-five thousand, one hundred thirteen".