150153120055131 has 4 divisors (see below), whose sum is σ = 200204160073512. Its totient is φ = 100102080036752.

The previous prime is 150153120055129. The next prime is 150153120055181. The reversal of 150153120055131 is 131550021351051.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 150153120055131 - 2¹ = 150153120055129 is a prime.

It is a super-2 number, since 2×150153120055131² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 150153120055092 and 150153120055101.

It is not an unprimeable number, because it can be changed into a prime (150153120055111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25025520009186 + ... + 25025520009191.

It is an arithmetic number, because the mean of its divisors is an integer number (50051040018378).

Almost surely, 2^{150153120055131} is an apocalyptic number.

150153120055131 is a deficient number, since it is larger than the sum of its proper divisors (50051040018381).

150153120055131 is an equidigital number, since it uses as much as digits as its factorization.

150153120055131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 50051040018380.

The product of its (nonzero) digits is 11250, while the sum is 33.

The spelling of 150153120055131 in words is "one hundred fifty trillion, one hundred fifty-three billion, one hundred twenty million, fifty-five thousand, one hundred thirty-one".